A) \[2:1\]
B) \[1:2\]
C) \[\sqrt{2}:1\]
D) \[\sqrt{3}:1\]
Correct Answer: C
Solution :
[c] \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{1}{2}\] Two particles having same kinetic energies \[{{k}_{1}}={{k}_{2}}\] \[\frac{1}{2}{{m}_{1}}v_{1}^{2}=\frac{1}{2}{{m}_{2}}V_{2}^{2}\] \[\frac{{{m}_{1}}}{{{m}_{2}}}={{\left[ \frac{{{v}_{2}}}{{{v}_{1}}} \right]}^{2}}\] \[\frac{1}{\sqrt{2}}=\frac{{{v}_{2}}}{{{v}_{1}}}\] \[{{v}_{1}}=\sqrt{2}\,\,{{v}_{2}}\] \[\lambda \propto \frac{1}{mv}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{{{m}_{2}}{{v}_{2}}}{{{m}_{1}}{{v}_{1}}}\] \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{2{{v}_{2}}}{\sqrt{2}{{v}_{2}}}=\frac{\sqrt{2}}{1}\]
You need to login to perform this action.
You will be redirected in
3 sec
