A) \[{{I}^{-}}>N{{H}_{3}}>R-N{{H}_{2}}>H{{S}^{-}}\]
B) \[N{{H}_{3}}>R-N{{H}_{2}}>H{{S}^{-}}>{{I}^{-}}\]
C) \[R-N{{H}_{2}}>N{{H}_{3}}>H{{S}^{-}}>{{I}^{-}}\]
D) \[H{{S}^{-}}>R-N{{H}_{2}}>N{{H}_{3}}>{{I}^{-}}\]
Correct Answer: C
Solution :
[c] \[R-N{{H}_{2}}>N{{H}_{3}}>H{{S}^{-}}>{{I}^{-}}\] The proton accepting tendency increases as the basicity of the amine increases or acidity of the acid decreases. Amongst, \[RN{{H}_{2}}\]and\[N{{H}_{3}}\],\[RN{{H}_{2}}\] is a stronger base than \[N{{H}_{3}}\] and amongst \[H{{S}^{-}}\] and \[{{I}^{-}},H{{S}^{-}}\] has a stronger tendency to accept a proton than \[{{I}^{-}}\] because \[{{H}_{2}}S\] is a weaker acid than HI. Therefore, the overall order is \[R-N{{H}_{2}}>N{{H}_{3}}>H{{S}^{-}}>{{I}^{-}}\].
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