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NEET Sample Paper NEET Sample Test Paper-59

  • question_answer
    An aqueous solution freezes at \[-\,0.186{}^\circ \,C\,({{K}_{f}}=1.86{}^\circ ;{{K}_{b}}=0.512{}^\circ ).\]What is the elevation in boiling point?

    A) 0.186                           

    B) 0.512   

    C) 0.86                             

    D) 0.0512

    Correct Answer: D

    Solution :

    [d] 0.0512 For the depression in freezing point \[\Delta {{T}_{f}}={{k}_{f}}\times m\] Where \[{{k}_{f}}\] is a constant known as molal depression constant. \[\Delta {{T}_{b}}={{k}_{b}}\times m\] (for boiling point elevation) Hence, \[\frac{\Delta {{T}_{b}}}{0.186}=\frac{0.512}{1.86}\] \[\Delta {{T}_{b}}=0.0512{}^\circ C\]


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