A) \[{{C}_{2}}{{H}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[{{C}_{2}}{{H}_{2}}B{{r}_{2}}\]
Correct Answer: C
Solution :
[c] \[{{C}_{2}}{{H}_{6}}\] As the size of the hybrid orbital of carbon forming C-H bond decreases in the order \[s{{p}^{3}}>s{{p}^{2}}>sp\] C-H bond distance decrease in the same order. In\[{{C}_{2}}{{H}_{6}}\],The orbital of carbon forming bond is \[S{{p}^{3}}\]and hence C-H bond distance is longest.
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