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NEET Sample Paper NEET Sample Test Paper-59

  • question_answer
    \[{{E}^{{}^\circ }}F{{e}^{2+}}/=\,Fe=-\,0.441V\] and \[{{E}^{{}^\circ }}{{F}^{3+}}=0.771V\] the standard EMF of the reaction, \[Fe+2F{{e}^{3+}}\to 3{{F}^{2+}}\]will be:

    A) 0.111V                         

    B) 0.330V

    C) 1.653V                         

    D) 1.212V

    Correct Answer: D

    Solution :

    [d] 1.212V Since \[E{}^\circ \,of\,F{{e}^{^{2+}}}/Fe\,\,is-\,\,0.441V\]i.e. lower than that of \[F{{e}^{3+}}/Fe\,\,{{24}^{2+}}\,which\,\,is\,\,(+\,0.771V)\]electrode. Therefore, oxidation occurs at \[F{{e}^{2+}}/Fe\] electrode and, reduction occurs at \[F{{e}^{3+}}/F{{e}^{2+}}\] electrode. \[\therefore \,\] \[EMF=E_{cathode\,}^{0}-E_{anode}^{0}\] \[=\,0.771\,V-[-0.441V]\] \[=0.771+0.441\] \[EMF=1.212V\]


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