A) \[\ell =1m,\,D=1mm\]
B) \[\ell =2m,\,D=2mm\]
C) \[\ell =2m,\,d=2mm\]
D) \[\ell =0.5m,\,D=0.5mm\]
Correct Answer: D
Solution :
[d] let \[\frac{F}{Y\pi }=K\] For wire 1, \[\Delta \ell =\frac{F}{Y\pi }\frac{1}{{{(1)}^{2}}}=K\] For wire 2, \[\Delta \ell =K.\frac{2}{{{(2)}^{2}}}=\frac{K}{2}\] For wire 3, \[\Delta \ell =K.\frac{2}{{{(3)}^{2}}}=\frac{K}{2}\] For wire 4, \[\Delta \ell =K.\frac{0.5}{{{(0.5)}^{2}}}=2K\] For wire 4, is largest
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