A) \[3\times {{10}^{8}}m/s\]
B) \[1.5\,\times {{10}^{8}}m/s\]
C) \[6\,\times {{10}^{8}}m/s\]
D) \[\sqrt{3}\,\times {{10}^{8}}m/s\]
Correct Answer: B
Solution :
[b] Cridcal angle \[C=30{}^\circ \] \[\mu =\frac{1}{Sin\,C}=\frac{1}{Sin\,30{}^\circ }\] \[\mu =2\] \[{{V}_{1}}=\frac{C\,(speed\,of\,light)}{\mu }\] \[{{V}_{1}}=\frac{3\times {{10}^{8}}}{2}\] \[{{V}_{1}}=1.5\times {{10}^{8}}m/s\]
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