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NEET Sample Paper NEET Sample Test Paper-59

  • question_answer
    A particle executes SHM with amplitude 0.2m and time period 24 sec The time require for it to move from mean position to a point 0.1 m from the mean position is:

    A) 12sec                           

    B) 3 sec    

    C) 2 sec                            

    D) 8 sec

    Correct Answer: C

    Solution :

    [c] Particle starts from mean position hence equation of motion used will be of sin \[x=A\,\sin \,\omega t[\phi =0]\] \[0.1=0.2\,\sin \,\frac{2\pi t}{T}\] \[0.1=0.2\,\sin \,\frac{2\pi t}{T}\] \[Sin\,\frac{\pi }{6}=Sin\,\frac{\pi t}{12}\] \[t=2\,\sec \] Note Particle starts from mean position use \[x=A\,\sin \,\omega \] If particle starts from any position except mean, use \[x=A\,\cos \,(\omega t+\phi )\]


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