NEET Sample Paper NEET Sample Test Paper-59

  • question_answer
    The length of the second's pendulum on the surface of earth is 1m. The length of second's pendulum on the surface of moon, where g is-tha value of earth surface, is:

    A) \[\frac{1}{6}m\]            

    B)   \[6m\]

    C) \[\frac{1}{36}m\]                      

    D) \[36m\]

    Correct Answer: A

    Solution :

    [a] \[Case-1\text{ }\,\,T=2\pi \sqrt{\frac{\ell }{g}}~~~~~~~~~~......(1)\]             \[2=2\pi \sqrt{\frac{\ell }{g}}~\] \[Case-2\text{ }\,\,T''\,\,2=2\pi \sqrt{\frac{\ell '}{{}^{g}/{}_{6}}}~~~~~~~~~~......(2)\] From (1) and (2) \[\ell '=\frac{1}{6}m\]


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