A) \[-\frac{1}{2},0,\frac{1}{2}\]
B) \[-\frac{1}{2},0,-\frac{1}{2}\]
C) \[0,-\frac{1}{2},\frac{1}{2}\]
D) \[0,\frac{1}{2},-\frac{1}{2}\]
Correct Answer: D
Solution :
[d] \[T\propto \,\,{{[M]}^{a}}\,{{[L]}^{b}}{{[L{{T}^{-2}}]}^{c}}\] \[T=K\,{{[M]}^{a}}\,\,\,\,{{L}^{b+c}}\,\,\,\,{{T}^{-2c}}\,\] \[a=0,\,-2c=1b+c=0\] \[\,c=-\frac{1}{2}b=\frac{1}{2}=0\] \[\,b=\frac{1}{2}\] \[a=0\,b=\frac{1}{2}\,\,\,\,\,\,\,\,c=-\frac{1}{2}\]You need to login to perform this action.
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