A) \[12\times {{10}^{-6}}J\]
B) \[24\times {{10}^{-6}}J\]
C) \[60\times {{10}^{-6}}J\]
D) \[96\times {{10}^{-6}}J\]
Correct Answer: B
Solution :
[b] \[Area=16\times {{10}^{-\,4}}\,4{{m}^{2}}\] \[Are{{a}_{2}}=20\times {{10}^{-4}}{{m}^{2}}\] \[\Delta \,A=(20\times {{10}^{-4}}-16\times {{10}^{-4}})\,\] \[\Delta \,A=4\times {{10}^{-4}}{{m}^{2}}\] Work done \[=2T\text{ }\Delta A\] \[\therefore \] ['2' for two film front & back side] \[=2\times 3\times {{10}^{-2}}\times 4\times {{10}^{-4}}\] \[=24\times {{10}^{-2}}J\]You need to login to perform this action.
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