A) 30s
B) 10s
C) 30, 000s
D) 10,000s
Correct Answer: A
Solution :
[a] 30s \[A{{l}^{3-}}+3{{e}^{-}}\xrightarrow{{}}Al\] One mole requires = \[3\times 96500C\] \[=3\times 96.5C\] \[\therefore \,\] One milli mole requires \[3\times \frac{96500C}{100}\] \[\therefore \text{ }3\times 96.5\text{ }C=\text{ }9.65\text{ }A\,\times \]Time in sec. \[\Rightarrow \,Time=\frac{3\times 96.5}{9.65}\text{ =30s}\]
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