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NEET Sample Paper NEET Sample Test Paper-55

  • question_answer
    In basic medium, \[CrO_{4}^{2-}\] oxidizes \[{{S}_{2}}O_{3}^{2-}\] to form \[SO_{4}^{2-}\] and itself changes to \[Cr\left( OH \right)_{4}^{-}\]. How many mL of 0.154 M \[CrO_{4}^{2-}\] are required to react with 40 mL of 0.246 M \[{{S}_{2}}O_{3}^{2-}\]?

    A) 200 mL                        

    B) 156.4 mL

    C) 170.4 mL                     

    D) 190.4 mL

    Correct Answer: C

    Solution :

    \[CrO_{4}^{-2}+{{S}_{2}}O_{3}^{-2}\xrightarrow{{}}SO_{4}^{-2}+Cr(O{{H}^{-}}){{~}_{4}}\] \[Eq.\,\,of\,\,CrO_{4}^{-2}=\,\,Eq.\,\,of\,\,{{S}_{2}}O_{3}^{-2}\] \[0.154\times 3\times V\,\,=\,\,0.246\times 8\times 40\] \[V\,\,=\,\,170.4\text{ }ml\]


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