A) It occupies 2.24 L at NTP
B) It corresponds to \[\frac{1}{2}\] mole of CO
C) It corresponds to same mole of CO and \[{{N}_{2}}\]
D) It corresponds to \[3.01\,\,\times \,\,{{10}^{23}}\] molecules of CO
Correct Answer: A
Solution :
\[{{V}_{CO}}=\frac{14}{28}\times 22.4=11.2\text{ }litre\]
You need to login to perform this action.
You will be redirected in
3 sec
