A) \[2m\,A\]
B) \[0.4\,\mu A\]
C) \[4.0\text{ }mA\]
D) \[4\,\mu A\]
Correct Answer: B
Solution :
\[I\,\,=\,\,1\text{ }W/{{m}^{2}}\] \[\lambda =\,\,5000\,\overset{{}^\circ }{\mathop{A}}\,\] \[A\,\,=\,\,1\text{ }c{{m}^{2}}={{10}^{-}}^{4}\,c{{m}^{2}}\] No. of incidenting photon \[n\,\,=\,\,\frac{I\times A}{hc}\lambda \] \[=\text{ }1\times {{10}^{-}}^{4}\times 5000\times 5\times {{10}^{15}}\] \[=\text{ }25\times {{10}^{13}}\] \[i=\frac{q}{t}=\frac{n\times \frac{1}{100}.\,e}{1}\,\,=25\times {{10}^{13}}\times 1.6\times {{10}^{-~19}}\times 10{{~}^{-2}}\] \[=\,\,40.0\,\,\times \,{{10}^{-8}}A\,\,=\,\,\,0.4\,\,\mu \text{A}\]
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