A) 200 K
B) 250 K
C) 173 K
D) 189 K
Correct Answer: D
Solution :
In case of adiabatic change, \[P{{V}^{\gamma }}=\,\,constt.\,\,with\,\,PV\,\,=\,\,\mu RT\] So, that \[{{T}_{1}}\,\,\,V_{1}^{\gamma -1}\,\,=\,\,{{T}_{2}}\,\,\,V_{2}^{\gamma -1}\,\,\,\,with\,\,\,\left[ \gamma \,\,=\,\,(5/3) \right]\] \[i.e,\text{ }300\,\,\times \,\,{{V}^{2/3}}=T{{\left( 2V \right)}^{2/3}}\] \[or\text{ }\,T=300/{{\left( 2 \right)}^{2/3}}=189\,\,K\]
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