| (I) \[N{{a}_{2}}C{{O}_{3}}\,\,\And \,\,CaC{{O}_{3}}\] |
| (II) \[MgC{{l}_{2}}.6{{H}_{2}}O\,\,\text{ }\!\!\And\!\!\text{ }\,\,CaC{{l}_{2}}.6{{H}_{2}}O\] |
| (III) \[Ca{{(N{{O}_{3}})}_{2}}\,\,\And \,\,NaN{{O}_{3}}\] |
A) I, II
B) I, II, III
C) I, III
D) I only
Correct Answer: B
Solution :
\[NaC{{O}_{3}}\xrightarrow{\Delta }\,\,\chi \] \[MgC{{l}_{2}}.6{{H}_{2}}O\xrightarrow{\Delta }\,\,Mg{{(OH)}_{2}}+HCl\] \[CaC{{l}_{2}}.6{{H}_{2}}O\text{ }\to CaC{{l}_{2}}+6{{H}_{2}}O\] \[NaN{{O}_{3}}\,\,\xrightarrow{\Delta }\,\,NaN{{O}_{2}}+\frac{1}{2}{{O}_{2}}\] \[Ca{{(N{{O}_{3}})}_{2}}\xrightarrow{\Delta }\,\,CaO+N{{O}_{2}}+{{O}_{2}}\]
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