A) \[8.1\,%\]
B) \[9.1\,%\]
C) \[10.1\,%\]
D) \[11.1\,%\]
Correct Answer: D
Solution :
Given \[\left( \frac{{{V}_{2}}}{{{V}_{1}}}-1 \right)\,\times \,100=-10\] \[\therefore \,\,\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{9}{10}\,\,\,\because \,\,\,\,P\propto \frac{1}{V}\] \[\therefore \,\,\left( \frac{{{P}_{2}}}{{{P}_{1}}}-1 \right)\times 100\,\,=\,\,\left( \frac{{{V}_{1}}}{{{V}_{2}}}-1 \right)\,\,\times \,\,100\] \[\therefore \text{ }%\text{ }change\text{ }in\text{ }pressure\text{ }=\left( \frac{10}{9}-1 \right)\times 100\] \[=\,\,11.1\,%\]
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