question_answer

In the circuit shown in the figure, the potential difference across the \[4.5\text{ }\mu F\] capacitor-

A) \[8\text{ }volt\]             

B) \[6\text{ }volt\]

C) \[4\text{ }volt\] 

D) \[\frac{8}{3}\,\,volt\]

Correct Answer: A

Solution :

\[{{V}_{1}}\,\,=\,\,\frac{{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}}\,\,\times \,\,V\,\,=\,\,\frac{9}{4.5+9}\,\times \,12\,V\]