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NEET Sample Paper NEET Sample Test Paper-53

  • question_answer
    The magnetic field due to a current carrying circular loop of radius 3 cm at a point on its axis at a distance of 4 cm from the centre is\[54\,\mu T\]. The magnetic field (in \[(in\,\,\mu T)\] at the centre of the loop will be

    A) 250                              

    B) 150   

    C) 125                              

    D) 72

    Correct Answer: A

    Solution :

    \[B=\frac{{{\mu }_{0}}NI{{R}^{2}}}{2{{({{x}^{2}}+{{R}^{2}})}^{3/2}}}\,\,=\,\,\frac{{{\mu }_{0}}NI{{(3)}^{2}}\times {{10}^{-4}}}{2{{(5)}^{3}}\times {{10}^{-6}}}\,\,=\,\,54\mu T\] \[{{B}_{centre}}\,\,=\,\,\frac{{{\mu }_{0}}NI}{2R}\,\,=\,\,\frac{{{\mu }_{0}}NI}{2\times 3\times {{10}^{-2}}}\]


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