A) \[{{C}_{1}}={{C}_{2}}\]
B) \[{{C}_{1}}>{{C}_{2}}\]
C) \[{{C}_{2}}>{{C}_{1}}\]
D) None of these
Correct Answer: C
Solution :
\[\Delta G\] will negative when \[{{E}_{cell}}\] will positive for given cell \[Zn/Zn_{({{C}_{1}})}^{+2}\,\,\parallel \,\,Zn_{({{C}_{2}})}^{+2}/Zn\] \[E_{cell}^{0}\,\,=\,\,0\] \[E_{cell}^{{}}\,\,=\,\,0\,\,-\,\frac{0.0591}{2}\,\log \,\left( \frac{{{C}_{1}}}{{{C}_{2}}} \right)\] Now if \[{{C}_{2}}>{{C}_{1}}\] then \[{{E}_{cell}}\] will positive because log \[\left( x\,\,<\,\,1 \right)\] is negative
You need to login to perform this action.
You will be redirected in
3 sec
