A) \[N{{a}_{2}}\left[ Fe{{\left( CN \right)}_{5}}S \right]\]
B) \[N{{a}_{2}}\left[ Fe{{\left( CN \right)}_{5}}NOS \right]\]
C) \[N{{a}_{4}}\left[ Fe{{\left( CN \right)}_{5}}NOS \right]\]
D) \[KFe\left[ Fe{{\left( CN \right)}_{5}}NO \right]\]
Correct Answer: C
Solution :
\[N{{a}_{2}}[Fe{{(CN)}_{5}}NO]+N{{a}_{2}}S\,\,\to \,\,N{{a}_{4}}[Fe{{(CN)}_{5}}NOS]\]
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