| \[C{{N}^{-}}\] |
| \[C{{N}^{-}}~+{{H}_{2}}O\rightleftharpoons HCN+O{{H}^{-}}\] |
A) \[{{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{a}}}\]
B) \[h=\sqrt{\frac{{{K}_{H}}}{C}}~\]
C) \[pH=\frac{1}{2}p{{K}_{a}}\]
D) \[[{{H}^{+}}]=\frac{{{K}_{w}}{{K}_{a}}}{C}\]
Correct Answer: C
Solution :
\[pH=\frac{1}{2}\left( p{{K}_{w}}+p{{K}_{a}}-log\,\,C \right)\]
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