question_answer

The potential difference between the points A and B in the following circuit will be-

A) zero                              

B) 2 V

C) 3.5 V               

D) 4.5 V

Correct Answer: D

Solution :

\[2I+2{{I}_{1}}-6=0\] \[I+{{I}_{1}}=3~~\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,~~~\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,....\left( 1 \right)\]\[\left( I-{{I}_{1}} \right)1+6-2{{I}_{1}}=0\] \[I-3{{I}_{1}}=-6~~~~~~~~~~~~....\left( 2 \right)\] From (1) & (2) \[\therefore \,\,\,{{I}_{1}}=9/4\] \[{{V}_{A}}-{{V}_{B}}=IR\] \[=\,\,\,9/4\times 2\] \[=9/2\,\,=\,\,4.5\]