A) \[{{I}_{0}}\,\cos \,\left( \frac{x}{\beta } \right)\]
B) \[{{I}_{0}}\,{{\cos }^{2}}\,\left( \frac{2\pi x}{\beta } \right)\]
C) \[{{I}_{0}}\,{{\cos }^{2}}\,\left( \frac{\pi x}{\beta } \right)\]
D) \[\frac{{{I}_{0}}}{4}\,{{\cos }^{2}}\,\frac{\pi x}{\beta }\]
Correct Answer: C
Solution :
\[\beta =\frac{\lambda D}{d}\] \[\Delta \,\,=\,\,\frac{dx}{D}\] \[\therefore \,\,\,\phi =\frac{d.x}{D.\lambda }\times \,\,2\pi \,\,=\,\,\frac{d.x}{D.\beta d}\,\,\times \,\,D\,\,=\,2\pi \frac{x}{\beta }\] \[\therefore \,\,\,I\,\,=\,\,{{I}_{0}}\,{{\cos }^{2}}\,\,\frac{\phi }{2}\,\,=\,\,{{I}_{0}}{{\cos }^{2}}\,\frac{\pi x}{\beta }\]
You need to login to perform this action.
You will be redirected in
3 sec
