question_answer

A particle of mass 'm' is projected from ground with velocity 'u' making angle '\[\theta \]' with the vertical. The de Broglie wavelength of the particle at the highest point is-

A) \[\infty \]                                   

B) \[h/mu\text{ }sin\text{ }\theta \]

C) \[h/mu\text{ }cos\text{ }\theta \]

D) \[h/mu\]

Correct Answer: B

Solution :

At highest \[pt\,\lambda \,\,=\,\,\frac{h}{mu\,\sin \,\theta }\]