• question_answer 69) In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking $Kf$ for water as 1.85, the freezing point of the solution will be nearest to- A) $-0.260{}^\circ C$                  B) $+\,0.480{}^\circ C$C) $-0.480{}^\circ C$                  D) $-0.360{}^\circ C$

$\Delta {{T}_{f}}={{K}_{f}}\times m$ ${{(\Delta {{T}_{f}})}_{obs.}}=i\times {{K}_{f}}\,\times \,m\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\alpha =\frac{i-1}{n-1}$ $=1.3\times 1.85\times 0.2\,\,\,0.3=\frac{i-1}{2-1}$ $=\,\,0.481$