• # question_answer A body moves is a circular path of radius $r\,\,=\,\,500\,\,\,m$ with tangential acceleration${{a}_{t}}=2\text{ }m{{s}^{-}}^{2}$. When its tangential linear velocity is $30\text{ }m/s$, the total acceleration will be: A) $5.4\text{ }m{{s}^{-}}^{2}$B) $3.9\text{ }m{{s}^{-}}^{2}$C) $2.7\,\,m{{s}^{-2}}$  D) $2.1\,\,m{{s}^{-}}^{2}$

Centripetal acceleration, ${{a}_{c}}=\frac{{{v}^{2}}}{r}\,\,=\,\,\frac{{{(30)}^{2}}}{500}\,\,=\,\,1.8\,m/s$ $\therefore \,\,\,\text{ }Total\text{ }acceleration,$ $a=\sqrt{{{({{a}_{c}})}^{2}}+{{({{a}_{t}})}^{2}}}$ $=\,\,\sqrt{{{(1.8)}^{2}}+{{(2)}^{2}}}\,\,=\,\,2.7m/{{s}^{2}}$