• # question_answer Two parallel plate of area A are separated by two different dielectrics as shown in figure. The net capacitance is- A) $\frac{4{{\varepsilon }_{0}}A}{3d}$B)               $\frac{3{{\varepsilon }_{0}}A}{4d}$C) $\frac{2{{\varepsilon }_{0}}A}{d}$                  D) $\frac{{{\varepsilon }_{0}}A}{d}$

${{C}_{0}}\,=\,\frac{{{\in }_{0}}A}{d}$ ${{C}_{1}}={{K}_{1}}\times 2{{C}_{0}}\text{ }\,\,2{{C}_{0}}{{K}_{2}}={{C}_{2}}$