A) \[FeC{{l}_{2}}\]
B) \[CdC{{l}_{2}}\],
C) \[MgC{{l}_{2}}\]
D) \[ZnC{{l}_{2}}\]
Correct Answer: D
Solution :
\[Z{{n}^{2+}},\] \[C{{d}^{2+}}\] and \[H{{g}^{2+}}\] all have pseudo inert gas configuration and hence are more polarising than \[F{{e}^{3+}}\] and \[M{{g}^{2+}}\] ions. Further smaller the cation, greater is its polarizing power and hence more covalent is the compound. The \[ZnC{{l}_{2}},\]has least ionic character.
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