A) \[h=\frac{5}{2}\,\,R\]
B) \[h=5R\]
C) \[h=8\,R\]
D) \[h=10\,R\]
Correct Answer: D
Solution :
From the conservation of energy, we get \[{{U}_{A}}=\sqrt{2gh}\] \[{{Y}_{B}}=\frac{2{{m}_{1}}{{U}_{A}}}{{{m}_{1}}+{{m}_{2}}}=\frac{{{U}_{A}}}{2}=\frac{\sqrt{2gh}}{2}\] And from the conservation of momentum, we get to complete vertical circle \[V_{B}^{2}=5gR\] \[\Rightarrow \] \[\frac{2gh}{4}=5gR\]
You need to login to perform this action.
You will be redirected in
3 sec
