NEET Sample Paper NEET Sample Test Paper-49

  • question_answer
    Calculate the enthalpy of reaction at 298 K for the reaction- \[{{C}_{2}}{{H}_{4}}\left( g \right)\,\,+\,\,6{{F}_{2}}\left( g \right)\,\,\to \,\,2C{{F}_{4}}\left( g \right)+4HF\left( g \right)\] by using following equations
    \[{{H}_{2}}\left( g \right)\,\,+\,\,{{F}_{2}}\left( g \right)\,\,\,\to \,\,2HF\left( g \right)\text{ }\Delta H\,\,=\,\,-537\text{ }kJ\] \[C\left( s \right)\,\,+\,\,2{{F}_{2}}\left( g \right)\,\,\to \,\,C{{F}_{4}}\left( g \right)\text{ }\Delta H\,\,=\,\,-680\text{ }kJ\] \[2C\left( s \right)\,\,+\,\,2{{H}_{2}}\left( g \right)\,\,\to \,\,{{C}_{2}}{{H}_{4}}\left( g \right)\text{ }\Delta H\,\,=\,\,52\text{ }kJ\]

    A) -1165 kJ                       

    B) -2486 kJ

    C) +1165 kJ                     

    D) +2486 kJ

    Correct Answer: B

    Solution :

    \[-Eq\left( 3 \right)\,\,+\,\,2x\text{ }eq\left( 2 \right)\,\,+\,\,2x\text{ }eq\left( 1 \right)=Desired\text{ }equation\]\[-\Delta {{H}_{3}}\,\,+\,\,2x\,\Delta {{H}_{2}}\,\,+\,\,2x\,\Delta {{H}_{1}}\,\,=\,\,\Delta H\] \[-52+\left( 2x-680 \right)+\left( 2x-537 \right)=\Delta H\] \[-52-1360-1074=-2486=\Delta H\]


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