A) \[\frac{4}{27}\]
B) \[\frac{2}{27}\]
C) \[\frac{8}{27}\]
D) \[\frac{4}{9}\]
Correct Answer: C
Solution :
\[v=\frac{d}{t}\,\,\,\,\therefore \,\,\,t=\frac{d}{v}\,=\,\,\frac{2\pi r}{v}\,\,=\,\,\frac{0.529\frac{{{n}^{2}}}{Z}}{2.18\times {{10}^{8}}\,\times \,\frac{Z}{n}}\] \[\therefore \,\,t\,\,\propto \,\,\frac{{{n}^{3}}}{{{Z}^{2}}}\,\] \[\therefore \,\,\,\,\frac{{{t}_{2}}}{{{t}_{3}}}\,\,=\,\,\frac{n_{2}^{3}}{2_{3}^{3}}\,\,=\,\,\frac{8}{27}\]
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