A) \[\left( 2.59\text{ }\widehat{k}+1.26\text{ }\widehat{j} \right)\times {{10}^{-}}^{2}\]
B) \[\left( 1.26\text{ }\widehat{k}-2.59\text{ }\widehat{j} \right)\times {{10}^{-}}^{2}\]
C) \[\left( -2.59\text{ }\widehat{k}-1.26\text{ }\widehat{j} \right)\times {{10}^{-}}^{2}\]
D) \[\left( -1.26\text{ }\widehat{k}+2.59\text{ }\widehat{j} \right)\times {{10}^{-}}^{2}\]
Correct Answer: A
Solution :
\[~F=I\left( \overrightarrow{l}\,\,\times \,\,\overrightarrow{B} \right)\] \[=3.5\left[ {{10}^{-2}}\widehat{i}\times (.75\widehat{j}-0.36\,\widehat{k} \right]]\] \[=\text{ }\left( 2.59\widehat{k}\text{ }+1.26\widehat{j} \right)\times {{10}^{-}}^{2}\]
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