A) \[180{}^\circ -A\]
B) \[180{}^\circ -2A\]
C) \[90{}^\circ -A\]
D) \[A/2\]
Correct Answer: B
Solution :
\[\cot \,\frac{A}{2}\,\,=\,\,\frac{\sin \,\left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \,\,A/2}\] \[\frac{\cos \,A/2}{\sin \,A/2}\,\,=\,\,\frac{\sin \,\left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \,\,A/2}\] \[\sin \,(90-A/2)\,\,=\,\,sin\,\left( \frac{A+{{\delta }_{m}}}{2} \right)\] \[so\,\,{{\delta }_{m}}\,\,=\,\,180{}^\circ -2A\]
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