A) nRT
B) 4nRT
C) 2nRT
D) 6Nrt
Correct Answer: D
Solution :
\[\operatorname{PV}=nRT\] \[V=\frac{nRT}{\operatorname{P}}\] \[V=\frac{nRT}{\operatorname{a}}\operatorname{T}=\frac{nR{{T}^{2}}}{\operatorname{a}}\therefore \Rho =\frac{a}{T}\] \[dV=\frac{2nRT}{\operatorname{a}}dt\] \[dW=\int\limits_{\operatorname{T}}^{4\operatorname{T}}{PdV}=\int\limits_{\operatorname{T}}^{4\operatorname{T}}{P.}\frac{2nRT}{\operatorname{a}}dt\int\limits_{\operatorname{T}}^{4\operatorname{T}}{\frac{a}{t}.\frac{2nRT}{\operatorname{a}}\operatorname{dt}}\] \[\operatorname{W}=6nRT\]
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