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NEET Sample Paper NEET Sample Test Paper-48

  • question_answer
    An ideal gas is taken through a cyclic thermo dynamical process through four steps \[{{\operatorname{Q}}_{4}}=\]3645J, respectively. The corresponding works involved are \[{{\operatorname{W}}_{1}}=2200J, {{W}_{2}}= -825\]J \[{{\operatorname{W}}_{3}} = -1100J and {{W}_{4}}\]respectively. The value of \[{{W}_{4}}\]is:

    A) 1315J                           

    B) 275J   

    C) 765J                            

    D) 675J

    Correct Answer: C

    Solution :

    \[\operatorname{In} a cyclic process \Delta U = 0\] 1st law of thermodynamics \[\operatorname{Q}=\Delta U+W\] \[{{\operatorname{Q}}_{1}}+ {{Q}_{2}}+{{Q}_{3}}+{{Q}_{4}}={{W}_{1}}+{{W}_{2}}+{{W}_{3}}+{{W}_{4}}\] \[5960-5585-2980+3645 =2200-825-1100+{{W}_{4}}\]\[{{\operatorname{W}}_{4}}= 1040-275\]  \[{{\operatorname{W}}_{4}}=765J\]


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