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NEET Sample Paper NEET Sample Test Paper-47

  • question_answer
    \[{{\operatorname{F}}_{2}}\]is formed by reaction of\[{{K}_{2}}Mn{{F}_{6}}\] with

    A) \[{{\operatorname{SbF}}_{3}}\]                        

    B) \[{{\operatorname{MnF}}_{3}}\] 

    C) \[{{\operatorname{kSbF}}_{6}}\]                      

    D) \[{{\operatorname{MnF}}_{5}}\]

    Correct Answer: A

    Solution :

    \[{{\operatorname{SbF}}_{5}}\] As the following reaction: \[2{{K}_{2}}{{M}_{n}}{{F}_{6}}+ 4Sb{{F}_{5}}\to 4KSb{{F}_{6}}+Mn{{F}_{3}}+ {{F}_{2}}\]


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