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NEET Sample Paper NEET Sample Test Paper-47

  • question_answer
    When 2- butyne is treated with dil. \[{{\operatorname{H}}_{2}}S{{O}_{4}}/\]\[{{\operatorname{HgSO}}_{4}}\], the product formed is:

    A) Butanol-1                     

    B) Butanol-2

    C) 2 - Butanone     

    D) Butanol

    Correct Answer: C

    Solution :

    (2-Butanone) \[\begin{align}   & \,\,\,\,\,\,\,\,\,\,\,\,\left( 2-Butyne \right) \\  & {{\operatorname{CH}}_{3}}-C\equiv C-C{{H}_{3}}+{{H}_{2}}O \xrightarrow{{{H}_{2}}S{{O}_{4}}/HgS{{O}_{4}}} \\ \end{align}\] \[\overset{1}{\mathop{\operatorname{C}}}\,{{H}_{3}}\overset{2}{\mathop{C}}\,O\overset{3}{\mathop{C}}\,{{H}_{2}}\overset{4}{\mathop{C}}\,{{H}_{3}}\] (2-Butanone)


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