A) 1:2
B) 1:1
C) 1: 16
D) 15:16
Correct Answer: D
Solution :
15:16 \[\operatorname{Given} {{W}_{{{H}_{2}}}}= {{W}_{{{C}_{2}}}} {{H}_{6}}\] Let height be Wg \[\therefore {{\operatorname{n}}_{{{H}_{2}}}}=\frac{W}{2},{{\operatorname{n}}_{{{\operatorname{C}}_{2}}}}{{H}_{6}}=\frac{W}{30}\] \[{{\operatorname{X}}_{{{H}_{2}}}}=\frac{W/2}{\frac{W}{2}+\frac{W}{30}}\] \[=\frac{\frac{1}{2}}{\frac{1}{2}+\frac{1}{30}}\] \[=\frac{1}{2}\times \frac{30}{16}=\frac{15}{16}\] \[{{\operatorname{P}}_{{{H}_{2}}}}={{X}_{{{H}_{2}}}}\times {{P}_{total}}=\left( 15/16 \right){{P}_{total}}\]
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