question_answer

Arrange the following in order of decreasing bond angle, giving reason: \[{{\operatorname{NO}}_{2}}, N{{O}^{+}}_{2}, N{{O}^{-}}_{2}\]

A) \[{{\operatorname{NO}}^{+}}_{2}> N{{O}_{2}}> N{{O}^{-}}_{2}\]          

B) \[{{\operatorname{NO}}^{-}}_{2}> N{{O}_{2}}> N{{O}^{+}}_{2}\]

C) \[{{\operatorname{NO}}_{2}}> N{{O}_{2}}^{-}>N{{O}^{+}}_{2}\]

D) \[{{\operatorname{NO}}_{2}}> N{{O}_{2}}^{-}>N{{O}^{+}}_{2}\]

Correct Answer: A

Solution :

\[{{\operatorname{NO}}^{+}}_{2} > N{{O}_{2}} > N{{O}^{-}}_{2}\] Because has no unshared electron and hence it is linear \[N{{O}_{2}}\]has one unshared electron while has one unshared electron pair.