A) \[{{\operatorname{M}}^{-}} \left( g \right) \to M \left( g \right)\]
B) \[\operatorname{M} \left( g \right) \to {{M}^{-}} \left( g \right)\]
C) \[{{\operatorname{M}}^{+}} \left( g \right) \to {{M}^{2+}} \left( g \right)\]
D) \[{{\operatorname{M}}^{2+}} \left( g \right) \to {{M}^{3+}} \left( g \right)\]
Correct Answer: D
Solution :
\[{{\operatorname{M}}^{2+}}\left( g \right)\to {{M}^{3+}}\left( g \right)\] \[{{\operatorname{M}}^{2+}}\left( g \right)-{{e}^{-}}\to {{M}^{3+}}\left( g \right)\] The removal of two electrons form neutral atom gives a doubly charged ion which will hold its remaining electrons even more tightly. As a resent, energy required to remove third electron from gaseous atom should be even more than the required for the second electron.
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