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NEET Sample Paper NEET Sample Test Paper-47

  • question_answer
    A \[2\mu F\] condenser is charged upto 200V and then battery is removed. On combining this with another uncharged condenser in parallel, the potential difference between two plates are found to be 40V. The capacity of second condenser is:

    A) \[2\mu F\]                     

    B) \[4\mu F\]   

    C) \[8\mu F\]                     

    D) \[16\mu F\]

    Correct Answer: C

    Solution :

    \[\operatorname{Voltage} across two plates = \frac{{{q}_{net}}}{{{C}_{net}}}\] \[40=\frac{2\times 200}{2\times \operatorname{C}}\] \[2+C=10\] \[C=8\mu \operatorname{F}\]


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