A) \[\frac{\left[ Z{{n}^{+2}} \right]}{\left[ C{{u}^{+2}} \right]}\,\,=\,\,{{10}^{2}}\]
B) \[\frac{\left[ Z{{n}^{+2}} \right]}{\left[ C{{u}^{+2}} \right]}\,\,=\,\,{{10}^{-\,2}}\]
C) \[\frac{\left[ Z{{n}^{+2}} \right]}{\left[ C{{u}^{+2}} \right]}\,\,=\,\,{{10}^{-\,4}}\]
D) \[\frac{\left[ Z{{n}^{+2}} \right]}{\left[ C{{u}^{+2}} \right]}\,\,=\,\,{{10}^{5}}\]
Correct Answer: D
Solution :
\[E-E{}^\circ \,\,=\,\,\frac{-0.0591}{2}\,\log \,\frac{\left[ Z{{n}^{+2}} \right]}{\left[ C{{u}^{+2}} \right]}\] \[\frac{-0.15}{0.0295}\,\,=\,\,\log \frac{[Z{{n}^{+2}}]}{[C{{u}^{+2}}]}\] \[5.0\,\,=\,\,\log \,\frac{[Z{{n}^{+2}}]}{[C{{u}^{+2}}]}\,\,\,or\,\,\frac{[Z{{n}^{+2}}]}{[C{{u}^{+2}}]}\,\,=\,\,{{10}^{5}}\]
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