A) \[N{{H}_{4}}N{{O}_{3}}\]
B) \[N{{H}_{4}}N{{O}_{2}}\]
C) \[Na{{N}_{3}}\]
D) [b], [c] both
Correct Answer: D
Solution :
\[N{{H}_{4}}N{{O}_{2}}\,\xrightarrow{\Delta }\,\,{{N}_{2}}+2{{H}_{2}}O\] \[Na{{N}_{3}}\,\,\xrightarrow{\Delta }\,\,Na+\frac{3}{2}\,{{N}_{2}}\] \[N{{H}_{4}}N{{O}_{3}}\xrightarrow{\Delta }\,\,{{N}_{2}}O+2{{H}_{2}}O\]
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