A) 493.6 kJ \[mo{{l}^{-}}^{1}\]
B) 13.12 kJ \[mo{{l}^{-}}^{1}\]
C) 13.6 kJ \[mo{{l}^{-}}^{1}\]
D) 93.6 kJ \[mo{{l}^{-}}^{1}\]
Correct Answer: A
Solution :
\[\lambda =242\,nm=242\times {{10}^{-}}^{9}\,m,\text{ }c=3\times {{10}^{8}}m{{s}^{-}}^{1}\] \[E\,\,=\,\,\frac{hc}{\lambda }\,\,=\,\,\frac{6.6256\times {{10}^{-34}}\times 3\times {{10}^{8}}\,}{242\times {{10}^{-9}}}\] \[=\text{ }0.082\,\,\times \,\,\text{1}{{0}^{-17}}\,J\] \[=\text{ }0.082\text{ }\times \text{ }{{10}^{-}}^{20}\] J for one atom fore one mole atom \[=\text{ }0.082\text{ }\times \text{ }{{10}^{-20}}\times \text{ }6.02\text{ }\times \text{ }{{10}^{23}}\,kJ\text{ }mo{{l}^{-}}^{1}\] \[=\,\,\,493.6\,\,kJ\,mo{{l}^{-1}}\]
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