A) \[1.92\times {{10}^{13}}\] Joule
B) \[3.84\times {{10}^{13}}\] Joule
C) \[3.2\times {{10}^{-}}^{11}\] Joule
D) \[1.6\times {{10}^{-}}^{1}\] Joule
Correct Answer: B
Solution :
\[470\text{ }gm=2\times 6\times {{10}^{23}}\,Nuclei\] \[\therefore \] Energy produced \[=\text{ }2\times 6\times {{10}^{23}}\times 200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\] \[=\,\,\,3.84\times {{10}^{13}}Joule\]
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