question_answer

The major product formed is:

A)

B)  

C)  

D)  

Correct Answer: C

Solution :

Since \[{{\operatorname{CH}}_{3}}O\] is a strong nucleophile as well as strong base, it can either bring about substitution or elimination. Now \[{{\operatorname{CH}}_{3}}\]group at P-carbon causes \[{{\operatorname{S}}_{N}}2\]therefore elimination occurs preferentially to form 2 methyl propene.