A) \[{{\operatorname{T}}_{1}} >{{T}_{2}}\]
B) \[{{\operatorname{T}}_{1}} <{{T}_{2}}\]
C) \[{{\operatorname{T}}_{1}} ={{T}_{2}}\]
D) \[{{\operatorname{T}}_{1}} >\,\,2{{T}_{2}}\]
Correct Answer: B
Solution :
\[{{\ell }_{1}}+{{\ell }_{2}}+{{\ell }_{3}}=110\] \[{{\operatorname{n}}_{1}}{{\ell }_{1}}={{\operatorname{n}}_{2}}{{\ell }_{2}}={{\operatorname{n}}_{3}}{{\ell }_{3}}\] \[\frac{{{\operatorname{n}}_{1}}}{{{\operatorname{n}}_{2}}}=\frac{1}{2}=\frac{{{\ell }_{2}}}{{{\ell }_{1}}}\,\,\,\,\,\,\,\,,\,\,\,\,\,\,\,\frac{{{\operatorname{n}}_{1}}}{{{\operatorname{n}}_{3}}}=\frac{1}{3}=\frac{{{\ell }_{3}}}{{{\ell }_{1}}}\] \[{{\ell }_{1}}+\frac{{{\ell }_{1}}}{2}+\frac{{{\ell }_{1}}}{3}=110\] \[{{\ell }_{1}}=60\operatorname{cm},\,\,{{\ell }_{2}}=30\operatorname{cm},\,\,\,{{\ell }_{3}}=20\operatorname{cm}\]
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