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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    The rate law for a reaction between the substances A and B is given by, rate\[=k{{[A]}^{n}}{{[B]}^{m}}\]. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as -

    A)      \[\frac{1}{{{2}^{(m+n)}}}\]               

    B) \[(m+n)\]

    C) \[\left( n-m \right)\]                     

    D) \[{{2}^{(n-m)}}\]

    Correct Answer: D

    Solution :

    \[R=K{{(A)}^{n}}{{(B)}^{m}}\] \[R'=K{{(2A)}^{n}}{{\left( \frac{B}{2} \right)}^{m}}\] \[=K{{(A)}^{n}}{{2}^{n}}{{(B)}^{m}}{{2}^{-m}}\] \[=K{{(A)}^{n}}{{(B)}^{m}}{{2}^{n-m}},\] \[\frac{R'}{R}=\frac{K{{(A)}^{n}}{{(B)}^{m}}{{2}^{n-m}}}{K{{(A)}^{n}}{{(B)}^{m}}}={{2}^{n-m}}\]


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